As searches on the AG1286401 return this PicAxeForum posting I wish to post information pertaining to the LCD supplied by SURPLUSTRONICS (Auckland, New Zealand)
My examples have the following markings for reference.
AG1286401 Ver.2
17 Sep 2001
There is no onboard negative voltage generator as IC5 and the surrounding capacitors have not been populated.
Note: Solder jumper JP4 is also in place. This connects pins 3 and 18 of the module.
i.e Vo and Vee are connected on the module via JP4.
So, besides the +5Volts (Pin2) and Ground (Pin1) needed to drive the controller portion of the module, a second voltage needs to be provided to drive the LCD and establish the desired contrast. With the module configured as described above (JP4 in place) this voltage can be connected to either Vo (Pin3) or Vee(Pin18). It would be better practice to connect to Vo(Pin3).
This voltage, which must be negative, should be connected via a variable resistor (preset/trimmer or potentiometer) so that a contrast control can be affected.
Experiments revealed that the best configuration is:
Potentiometer / variable resistor = 10K Ohm
-10V to -12V (Bottom of potentiometer). (EDIT: 26/12/08)
Ground (Top of potentiometer)
Measured at the pot wiper...at -9V all pixels just start to turn on at full contrast setting. The effect is quite subtle and there is not enough contrast for those pixels that should be turned on. So a -9V supply is insufficent with any image very pale. With -10V the background pixels are obviously turning on and this is the best contrast setting for an image.With -12V all pixels are distinctly dark.
Use of the 10K potentiometer provides a control that is not too sensitive. I found 20K was to sensitive to set the desired contrast. (EDIT: 26/12/08)
As this display needs a healthy amount of negative voltage, connecting the top of the potentiometer to Ground (0Volts), as opposed to +5V, also makes the contrast control less sensitive.
LED BACKLIGHTING
NOTE: This display has no current limiting resistors in place for the LED backlighting.
You should insert a series resistor to limit the current. The back light configuration has 76 LEDs. 38 paralleled sets of 2 LEDs in series. The datasheet indicates up to 390mA for the back light so this indicates 10mA per LED
When supplying the LED back light from +5V, a series resistor of 4.7 Ohms will give a LED current typically around 200mA and with a spread 150mA to 300ma going by the Forward Voltage Max/Min figures in the datasheet.
EDIT: 12/12/08 With +5V the following LED currents were measured.
4.7 Ohm series resistor gave 195mA (At a brightness level I preferred)
5.1 Ohm series resistor gave 186mA (Possibly a brightness level a little low)
EDIT 6/1/09
MISSING NEGATIVE VOLTAGE GENERATOR CIRCUITRY
For those interested the missing IC is an Epson SCI7661
R7 =1Meg, and C1,C2 and C7 would be 10uF 16V
Check the SCI7661 datasheet for the configuration needed to attain the -10Volts
As I write this there is a SCI7661 source on eBay US$9 plus freight of US$5 to NZ. Ex Hong Kong
The jumpers will need addressing. Un-solder JP4 and deduce what should be done with JP1 thru JP3 using the datasheet.
I hope you find this information useful.