I have a small project using an 08M chip and a PIR. The PIR requires 4-15vdc while the chip obvously takes 5v.
I'd like to power both devices with a common source and my plan was to use two 3.0v coin-cell batteries (cr2025) in a double stack holder along with the 8-pin proto kit (sans the battery leads).
The unit will be left outdoors unattended and I'd like it to run for many many months before the batteries need changing.
My question(s):
1) obviously the 6v supply will kill the chip so I'm looking at this MCP1700 voltage regulator. Is there any reason why this regulator could be insufficient to drive both devices?
2) how long will the chip run (approx) from this power source? The PIR is passive and sec sheets say it pulls a measily 45uA average. So i imagine alone without the chip sipping power it would run for a really long time.
Not sure if it matters but the code is only 10 or 12 lines and uses only 1 input and 1 output; the output goes to a self-powered totalizer. I may incorporate a micro LED on the output also but that's not necessary since the whole thing will be inclosed and the LED would be redundant anyway.
I'd like to power both devices with a common source and my plan was to use two 3.0v coin-cell batteries (cr2025) in a double stack holder along with the 8-pin proto kit (sans the battery leads).
The unit will be left outdoors unattended and I'd like it to run for many many months before the batteries need changing.
My question(s):
1) obviously the 6v supply will kill the chip so I'm looking at this MCP1700 voltage regulator. Is there any reason why this regulator could be insufficient to drive both devices?
2) how long will the chip run (approx) from this power source? The PIR is passive and sec sheets say it pulls a measily 45uA average. So i imagine alone without the chip sipping power it would run for a really long time.
Not sure if it matters but the code is only 10 or 12 lines and uses only 1 input and 1 output; the output goes to a self-powered totalizer. I may incorporate a micro LED on the output also but that's not necessary since the whole thing will be inclosed and the LED would be redundant anyway.