On the assumption that what you seem to have appears to be an integrator or series pass filter, I believe that what you need looks something like this, a low pass fiter to knock off the corners (high frequency harmonics). The inductor might be easily replaced by a resistor, which might be easier to change the value of.
Try this Low pass filter calculator
Enter a cutoff frequency, say 60kHz so that the second and subsequent harmonics are attenuated significantly.
Impedance, as you wish depending on your application, but 50Ohm is
Frequency response ripple. I guess at 0.5dB
Number of components, 3 for the Pi filter I have shown. This sort of circuit is good for transmitter outputs, so is probably good for you.
On the question of images: I use Linux and the drawing editor that I use exports .PNG files and my image was way too large for the forum. So I use the facilities of ImageMagick. Specifically the convert command, which just happens to be built into the Bash shell. IM is a cross platform program that will cost you nothing and is extremely powerful. Googling for the operations you want will give you a multitude of appropriate examples. It's available for Windows, so please give it a go, although I am unsure of the nature of the Windows interface.
From the Linux command line changing the type of an image and writing to a new file is as simple as:
convert mypicture.png mypicture.jpg
resizing an image:
convert mypicture,png -resize 30% mynewpicture,png
Resizing and changing the image type in one go:
convert Lpf.png -resize 30% Lpf.jpg
Nic12ab is absolutely right of course.
You might try connecting your C1 so that one end is to earth and the other end is joined to the junction of the two transistors as at present and the inductor there too.
A general rule of thumb that will get me into trouble with Hippy, Dippy, Manuka, WA55 and a few more no doubt.
When drawn in the conventional manner -
Plates of the capacitors Horizontal = low pass filter
Plates of the capacitors Vertical = high pass filter
With reservations:
The effective impedance of a given capacitor will increase as the frequency becomes lower. (the high frequency impedance may be affected by the type of construction (wound will have an element of inductance and electrolytic an element of resistance). As the frequency becomes DC, the capacitor is seen as an open circuit.
The effective impedance of of a given inductor will decrease as the frequency becomes lower At
steady DC it is effectively a pure resistance and at high frequency can be seen as a brick wall. Manuka will tell you about "metal insulators" on parallel feed lines if you ask nicely . . .
I kid you not.
Armed with those snippets of information you will make Dippy swoon (he will probably have a FET), but you will have an idea of what is going on. The descriptions I have given are of necessity simplistic and omit to mention phase changes, but that's making things more difficult.
I hope that if I haven't been helpful, then I have at least been mildly amusing.