Dig Command Question

[Dave E]

I am trying to print a number to a LCD. The number is in a byte of memory but I need to print a decimal point between digit 0 and digit 1. For example, if the number in memory is 155 it represents a voltage of 15.5 volts. My code includes the line:
B3 = B1 DIG 0
I get a syntax error on this line.
What is wrong with it?
I have also used B3 = B1 DIG 0 + "0" with the same results.

The manual states that The DIG command returns the decimal value of a 16 bit number. Therefore digit 0 of '67890' is 0 and digit 3 is '7'. To return an ascii value of the digit simply add ascii "0" to the digit value e.g.
let b1 = b2 DIG 0 + "0".
Since I want the decimal value of a number I assume that B1 = B2 DIG 0 is the correct syntax to use.

What I would like to use is somthing like this:
Serout 4, T2400, (#B1 DIG 2, #B1 DIG 1, ".", #B1 DIG 0)

Any ideas what I am doing wrong?

Dave

 

[eclectic]

Dave.

Firstly, what Picaxe are you using?

The DIG command only works with X1 / X2 parts.

e

 

[Dave E]

Oops.
I'm using an 08M.
Thanks eclectic, I missed that. I'll have to come up with another way to break out the individual digits.

Dave

 

[Brietech]

if say you wanted to print b0, but you want the last digit to be behind a decimal point:

b1 = b0 / 10 'upper part of number
b2 = b0 // 10 'gets the remainder

sertxd(#b1,".",#b2)

 

[eclectic]

Actually, there IS a way.

/10
//10

BUT, that'll be part of the fun of learning.

Look at Manual 2, page 19.
Initially Brain-boiling, but ............
e

 

[Dave E]

That's the way I've done it in the past. It does the job just fine but uses a bit more code/memory.

Dave